MATH SOLVE

4 months ago

Q:
# Given that the hypotenuse of this right triangle is 25 cm long and that tan(Θ) = 3 Find the values of x and y, accurate to the nearest tenth. A) x ≈ 7.9; y ≈ 23.7 B) x ≈ 23.7; y ≈ 7.9 C) x ≈ 7.9; y ≈ 26.4 D) x ≈ 26.4; y ≈ 79.1

Accepted Solution

A:

The wording of this problem indicates that there was an illustration. Could you possibly share that illustration?

Working without an illustration:

If tan theta = 3, then tan theta = opp/adj = 3/1. This tells us that the opp side is 3 times as long as is the adj. side. Let x be the shorter side, i. e., let x represent the adjacent side; then y is the longer side and represents the opposite side.

Then y = 3x (the opp side is 3x the adj side in length).

Applying the Pyth. Thm. a^2 + b^2 = c^2,

x^2 + (3x)^2 = hyp^2 = (25 cm.)^2

So x^2 + 9x^2 = (625 cm^2)

10x^2 = 625 cm^2, or x^2 = (625 cm^2) / 10 = 62.5 cm^2

x = 7.91 cm. Therefore, y = 3(7.91) = 23.72 cm.

We were supposed to round off these answers to the nearest 10th cm.

Therefore, x = 7.9 cm and y = 23.7 cm

Would that be A, B, C or D?

Working without an illustration:

If tan theta = 3, then tan theta = opp/adj = 3/1. This tells us that the opp side is 3 times as long as is the adj. side. Let x be the shorter side, i. e., let x represent the adjacent side; then y is the longer side and represents the opposite side.

Then y = 3x (the opp side is 3x the adj side in length).

Applying the Pyth. Thm. a^2 + b^2 = c^2,

x^2 + (3x)^2 = hyp^2 = (25 cm.)^2

So x^2 + 9x^2 = (625 cm^2)

10x^2 = 625 cm^2, or x^2 = (625 cm^2) / 10 = 62.5 cm^2

x = 7.91 cm. Therefore, y = 3(7.91) = 23.72 cm.

We were supposed to round off these answers to the nearest 10th cm.

Therefore, x = 7.9 cm and y = 23.7 cm

Would that be A, B, C or D?